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Evelinaivy2179
a fost răspuns

Descompuneti in factori:
a) 4x-8
b) 16a²-9b²
c) x²+3x+2

Răspuns :

[tex]\diplaystyle\mathtt{4x-8=\sqrt{4x}^2-\sqrt8^2=(\sqrt{4x}-\sqrt8)(\sqrt{4x}+\sqrt8)=(2\sqrt{x}-2\sqrt2)(2\sqrt{x}+2\sqrt2)} \\ \\ \mathtt{16a^2-9b^2=(4a)^2-(3b)^2=(4a-3b)(4a+3b)} \\ \\ \mathtt{x^2+3x+2=(x+1)(x+2)}[/tex]

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