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NOTEZ CU Î-Întregi şi s-supra

2î 4s3×(1î 1s2-2s5)+(0,75 +5s6):19s6=??


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Răspuns :

Ancarodica
10/3×(⁵⁾3/2 -²⁾2/5)+(75/100⁽²⁵+5/6)÷19/6=10/3×(15/10 -4/10)+(³⁾3/4+²⁾5/6)×6/19=
10/3×11/10+(9/12+10/12)×6/19=11/3+19/12×6/19=²⁾11/3+³⁾1/2=22/6+3/6=25/6=
4intregi si 1/6

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