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StarStable
a fost răspuns

Nr direct proportionale cu 4, 5 si 8 si 2a+3b+5c=100

Răspuns :

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{a,b,c} DP {4,5,8}⇔a/4=b/5=c/8=k
a=4k
b=5k
c=8k
2a+3b+5c=100⇔2*4k+3*5k+5*8k=100⇔k(8+15+40)=100
k*63=100
k=100/63
a=4*100/63=400/63
b=5*100/63=500/63
c=8*100/63=800/63