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Varog ajutati-ma , îmi trebuie urgent!!!!
Daca a+b=3,2 si b+c=5,3 , calculați :
a) 4a + 5b + c ;
b) 2a + 7b + 5c ;
c)3a + 10b + 7c ;
d) 10a + 12b + 2c .
Mulțumesc!!!

Răspuns :

a) 4a+4b+b+c=4(a+b)+b+c=4*3.2+5.3=12.8+5.3=18.1

b) 2a+2b+5b+5c=2(a+b)+5(b+c)=2*3.2+5*5.3=6.4+26.5=32.9

c) 3a+3b+7b+7c=3(a+b)+7(b+c)=3*3.2+7*5.3=9.6+37.1=46.7

d) 10a+10b+2b+2c=10(a+b)+2(b+c)=10*3.2+2*5.3=32+10.6=42.6

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