a+b+c = 3 333
b =3 × a:2
c = 2×b
a |____|____|
b |____|____|____|
c |____|____|____|____|____|____|
avem 11 segmente egale = 3 333
3 333 : 11 = 303 ( un segment)
a = 2×303 = 606
b = 3×303 = 909
c = 6×303 = 1 818
Verificare:
606 + 909 + 1 818 = 3 333
Cele 3 numere sunt:
606; 909; 1 818 .
