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AlexaZM
a fost răspuns

Se considera expresia E(x) =(x-3)²-16/x+1 : x²-7x/x, unde x este numar real. Aratati ca E(x)=1.

Răspuns :

[tex]E(x)= \frac{(x-3)^2-16}{x+1} : \frac{x^2-7x}{x} \\ E(x)= \frac{x^2-6x+9-16}{x+1} * \frac{x}{x(x-7)} \\ E(x)= \frac{x^2-6x-7}{x+1} *\frac{x}{x(x-7)} \\ E(x)= \frac{(x-7)(x+1)}{(x+1)} *\frac{x}{x(x-7)} \\ E(x)= \frac{x}{x} \\ E(x)=1[/tex]

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