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Damianrotar
a fost răspuns

cum ar drebui efectuate operatilein ordine 1-(27:9+32:4+48:8+54:6+30:5+18:6)x(7-42:6)=

Răspuns :

Ioanaionescu1
mai intai se afectueaza ridicarile la putere,apoi inmultirile si impartirile si apoi adunarile si  scaderile
ExpertGames112
(27:9+32:4+48:8+54:6+30:5+18:6)x(7-42:6)=0
(3+32:4+48:8+54:6+30:5+18:6)x(7-7)=0
(3+8+48:8+54:6+30:5+18:6)x0=0
(3+8+6+54:6+30:5+18:6)x0=0
(3+8+6+9+6+18:6)x0=0
(3+8+6+9+3)x0=0
(11+6+9+3)x0=0
(17+9+3)x0=0
(26+3)x0=0
29x0=0

=0 deorece orice numar inmultit cu zero da zero
Sper ca te-am ajutat!
Succes la scoala!

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