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[(B+260:2):3+3]+5-12=1997

Răspuns :

Sanduurzica
[(B+260:2):3+3]+5=1997+12    (se aplica metoda mersului invers)
[(B+130):3+3]+5=2009
[(B+130):3+3)=2009-5
(B+130):3+3=2004
(B+130):3=2004-3
(B+130):3=2001
B+130=2001x3
B+130=6003
B=6003-130
B=5873
[(B+260:2):3+3]+5-12=1997
[(B+130):3+3]+5-12=1997
[B+130 totul /3 + 3]+5-12=1997
B+130 totul /3+3+5-12=1997
B+130 totul /3 -4=1997 {amplifici cu 3}
B+130-13=5991
B+118=5991
B=5991-118
B=5873