ab:15 = c rest
r = 2×c+7 r<15
ab = 15×c+2×c+7
ab = 17×c+7
daca c= 1
ab = 17+7 = 24
24:15 = 1 rest 9
9 = 2×1+7
daca c=2
ab = 17×2+7 = 34+7 = 41
41:15 = 2 rest 11
11 = 2×2+7
daca c= 3
ab = 17×3+7 = 51+7 = 58
58 : 15 = 3 rest 13
13 = 2×3+7
Numerele sunt:
24; 41; 58 .
