Răspuns :
a) x=[tex] \frac{3*10}{5} =6[/tex]
b) [tex]x= \frac{15*7}{21} = \frac{15}{3}=5 [/tex]
c) [tex] \frac{x+2}{x+7} = \frac{3(x+2)}{48} [/tex]
x+2 se simplifica , 3 cu 48 la fel si ramane
[tex] \frac{1}{x+7}= \frac{1}{16} [/tex]
x+7=16
x=16-7=9
b) [tex]x= \frac{15*7}{21} = \frac{15}{3}=5 [/tex]
c) [tex] \frac{x+2}{x+7} = \frac{3(x+2)}{48} [/tex]
x+2 se simplifica , 3 cu 48 la fel si ramane
[tex] \frac{1}{x+7}= \frac{1}{16} [/tex]
x+7=16
x=16-7=9
a)3/5=x/10
5x=3 x 10
5x=30
x=30 :5=6
x=6
b) 7/x=21/15
21x=7 x 15
21x=105
x=105:21=5
x=5
c) x+2/x+7=3x+6/48
simplificam 3x+6/48 cu 3 si obtinem x+2/16
x+7=16
x=16-7
x=9
5x=3 x 10
5x=30
x=30 :5=6
x=6
b) 7/x=21/15
21x=7 x 15
21x=105
x=105:21=5
x=5
c) x+2/x+7=3x+6/48
simplificam 3x+6/48 cu 3 si obtinem x+2/16
x+7=16
x=16-7
x=9