[tex](a+b)^{12},are,13,termeni,in,mijloc,este,T_{7}= C^{6}_{12}a^6b^6 [/tex]
[tex](a+b)^{19},are,20,termeni, [/tex] in mijloc sunt doi termeni al 10-lea si al 11 -lea , adica T10 si T11[tex],deci[tex]T_{9+1}= C^{9}_{19}a^{10}b^9,si,T_{10+1}= C^{10}_{10+1}a^9b^{10} [/tex],
