Răspuns :
a=merii
b=peri
c=prune
a=(a+b+c):3
b=1 supra 2 50
b=25
c=50
a=(a+25+30):3
a=a+55:3
a=18.33
18.33+25+50=73.33
b=peri
c=prune
a=(a+b+c):3
b=1 supra 2 50
b=25
c=50
a=(a+25+30):3
a=a+55:3
a=18.33
18.33+25+50=73.33
m+p+p=x pomi fructiferi
m=1/3(x)
peri=(x-1/3(x)):2..=>peri =(rest 1):2
pruni=50...=>pruni =(rest 2)
---------------------------------------------
m=?p=?p=? x) |_____|_____|_____|=>m+p+p
m) \--------/1/3 din x
|_____|_____|=>rest 1
p) \--------/=>(rest1):2
|_____|=>rest 2
pruni) \--------/=>50
------------------------------------------------
x=pruni *3......=>x=50*3
x=150 pomi fructiferi
meri =150:3
=50 meri
150-50= 100 pomi fructiferi (rest 1)
peri=100:2
=50 peri
100-50=50 pruni ramasi ( rest 2)
50+50+50=150 pomi fructiferi in total
m=1/3(x)
peri=(x-1/3(x)):2..=>peri =(rest 1):2
pruni=50...=>pruni =(rest 2)
---------------------------------------------
m=?p=?p=? x) |_____|_____|_____|=>m+p+p
m) \--------/1/3 din x
|_____|_____|=>rest 1
p) \--------/=>(rest1):2
|_____|=>rest 2
pruni) \--------/=>50
------------------------------------------------
x=pruni *3......=>x=50*3
x=150 pomi fructiferi
meri =150:3
=50 meri
150-50= 100 pomi fructiferi (rest 1)
peri=100:2
=50 peri
100-50=50 pruni ramasi ( rest 2)
50+50+50=150 pomi fructiferi in total