Răspuns :
Se da:
k=250N/m
x=5cm=0,05m
m=1g=0,001kg
v=?m/s
Formule:
[tex]Ec=Ep\\ \frac{mv^{2}}{2}= \frac{kx^{2}}{2}\\ mv^{2}=kx^{2}\\ v= \sqrt{ \frac{kx^{2}}{m} }\\ Calcule:\\ v= \sqrt{ \frac{250*0,05^{2}}{0,001} }=25 \frac{m}{s} [/tex]
k=250N/m
x=5cm=0,05m
m=1g=0,001kg
v=?m/s
Formule:
[tex]Ec=Ep\\ \frac{mv^{2}}{2}= \frac{kx^{2}}{2}\\ mv^{2}=kx^{2}\\ v= \sqrt{ \frac{kx^{2}}{m} }\\ Calcule:\\ v= \sqrt{ \frac{250*0,05^{2}}{0,001} }=25 \frac{m}{s} [/tex]
[tex]\diplaystyle\mathtt{m=1g=0,001kg} \\ \\ \mathtt{\Delta l=5cm=0,05m} \\ \\ \mathtt{k=250\frac{N}{m}} \\ \\ \mathtt{\text{Energia se conserva , aceasta transformandu-se}} \\ \\ \mathtt{\text{din energie potentiala elastica in energie cinetica}} \\ \\ \mathtt{\frac{k\Delta l^2}{2}=\frac{mv^2}{2}} \\ \\ \mathtt{k\Delta l^2=mv^2} \\ \\ \mathtt{v=\sqrt{\frac{k\Delta l^2}{m}}} \\ \\ \boxed{\mathtt{v=25\frac{m}{s}}}[/tex]
