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AJUTORR!!DAU COROANA!! !!sa se det c(=concentratia) procentuala a solutiei obtinute prin dizolvarea a 36 g CuSO4*5H2O in 70g apa.sa se det c procentuala a solutiei finale.

Răspuns :

Masa moleculara CuSO4=64+32+16x4=160
Masa moleculara cristalohidrat (Cu SO4x5H2O)= 160+5x18=160+90=350g
350gCuSO4x5H2O.......................160g CuSO4..........................90g H2O
36g..................................................a..............................................b

a=160x36:350=16,457g
b= 90x36:350=19,543g
Cp=mdx100/ms
cp=(16,457x100):(70+19,543)=18,38%

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