a+b+c+d+e = 25
a |___|
b |___|+2
c |___|+4
d |___|+6
e |___|+8
avem 5 segmente egale +2+4+6+8 = 25
25 - (2+4+6+8) = 25-20 = 5
5 : 5 = 1 ( un segment)
a = 1
b = 1+2 = 3
c = 1+4 = 5
d = 1+6 = 7
e = 1+8 = 9
Verificare:
1+3+5+7+9 = 10+10+5 = 25
Numerele consecutive impare sunt:
1; 3 ; 5; 7; 9
