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F:r->r f(x)=2x-3, s=f(1)+f(2)+...+f(50)=? Urgent¡

Răspuns :

Albatran
f(1)=1
f(2)=3
f(3)=5
...............

f(49)=95


f(50)=97


f(1)+f(2)+...+f(50)=1+3+5+....+95+97= 98+98+...+98 de 50/2=25 ori
s=98*25=9800/4=2450
Crisanemanuel
....................................
Vezi imaginea Crisanemanuel

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