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Marius346
a fost răspuns

(X+2) la puterea 2 +(x -3) la a 2 -(x+1)(x-1)
(2x+1)la a 2 -(x-6)(x+6)-3(x-2
(x-5)(la a 2-(x-4)(x+4)+(x+1) la puterea a 2

Răspuns :

Renatemambouko
(x+2)²+(x -3)² -(x+1)(x-1)=
=x²+4x+4+x²-6x+9 -x²+1=
=x²-2x+14


(2x+1)² -(x-6)(x+6)-3(x-2)=
=4x²+4x+1 -x²+36-3x+6=
=3x²+x+43

(x-5)²-(x-4)(x+4)+(x+1)²=.
=x²-10x+25-x²+16+x²+2x+1=
=x²-8x+42

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