m = 168g MgCO₃
MMgCO₃ = AMg+AC+3AO = 24+12+3*16 = 84g/mol
n=m/M = 168/84 = 2 moli MgCO₃
MgCO₃ ---(t°C)---> MgO + CO₂↑
nMgCO₃ = n MgO = nCO₂ = 2 moli., Reactia este mol la mol, deci vor corespunde tot 2 moli de MgO si CO₂..
1mol.......................120g
MgO + H₂SO₄ ⇒ MgSO₄↓ + H₂O
2 moli........................xg
x=120*2 = 240g MgSO4
MMgSO₄ = 120g/mol
1mol......100g
Ca(OH)₂ + CO₂ ⇒ CaCO₃↓ + H₂O
2 moli,.......xg
x= 2*100 = 200g CaCO₃
MCaCO₃ = 100g/mol
