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Bonciumaria96
a fost răspuns

(3 √2-x)(3 √2+x)-(3x-2 √2)(3x+2 √2)+( √10x-1)( √10x+1)=

Răspuns :

CarMina03
(3 √2-x)(3 √2+x)-(3x-2 √2)(3x+2 √2)+( √10x-1)( √10x+1)=(3√2)²-x²-(3x)²+(2√2)²+(√10x)²-1²=18-x²-9x²+8+10x-1=25+10x-10x²

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