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sin³x+cos³x=(sinx+cosx)(1-sinxcosx)
Urgent va rog !

Răspuns :

[tex]\text{Aplicam formula:} \boxed{a^3+b^3=(a+b)(a^2-ab+b^2)}\\ \sin^3x+\cos^3x=(\sin x+\cos x)(\sin^2x-\sin x\cdot \cos x+\cos^2x).\\ \text{Stiind ca:}\boxed{\sin^2x+cos^2x=1},obtinem:\\ \sin^3x+\cos^3x=(\sin x+\cos x)(1-\sin x\cdot \cos x),c.c.t.d[/tex]

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