Răspuns :
1. a) 11 /√2 es amplifica cu √2=11√2 / 2
b) 6 /√7 se amplifica cu √7=6√7 / 7
c) 11/√3 se amplifica cu √3=11√3 / 3
d) 7/√10 se amplifica cu √10=7√10 /10
e) - 2 /√3 se amplifica cu √3= - 2√3/3
2. a) 4 /√2 se amplifica cu √2=4√2/2⁽²=2√2
b) 6/√6 se amplifica cu √6=6√6/6=√6
c) - 9 /√3 se amplifica cu √3= -9√3/3= -3√3
d) 21/√14 se amplifica cu √14=21√14/14 ⁽⁷=3√14/2
e) 5/√10 se amplifica cu √10= 5√10/10⁽⁵=√10/2
b) 6 /√7 se amplifica cu √7=6√7 / 7
c) 11/√3 se amplifica cu √3=11√3 / 3
d) 7/√10 se amplifica cu √10=7√10 /10
e) - 2 /√3 se amplifica cu √3= - 2√3/3
2. a) 4 /√2 se amplifica cu √2=4√2/2⁽²=2√2
b) 6/√6 se amplifica cu √6=6√6/6=√6
c) - 9 /√3 se amplifica cu √3= -9√3/3= -3√3
d) 21/√14 se amplifica cu √14=21√14/14 ⁽⁷=3√14/2
e) 5/√10 se amplifica cu √10= 5√10/10⁽⁵=√10/2
1. a) [tex] \frac{11}{ \sqrt{2} } [/tex] = [tex] \frac{11 \sqrt{2} }{2} [/tex]
b) [tex] \frac{6}{ \sqrt{7} } = \frac{6 \sqrt{7} }{7} [/tex]
c) [tex] \frac{11}{ \sqrt{3} } = \frac{11 \sqrt{3} }{3} [/tex]
d) [tex] \frac{7}{ \sqrt{10} } = \frac{7 \sqrt{10} }{10} [/tex]
e) [tex]- \frac{2}{ \sqrt{3} } = - \frac{2 \sqrt{3} }{3 } [/tex]
2. a) [tex] \frac{4}{ \sqrt{2} } = \frac{4 \sqrt{2} }{2} = 2 \sqrt{2} [/tex]
b) [tex] \frac{6}{ \sqrt{6} } = \frac{6 \sqrt{6} }{6} = \sqrt{6} [/tex]
c) [tex]- \frac{9}{ \sqrt{3} } = \frac{9 \sqrt{3} }{3} = 3\sqrt{3} [/tex]
d)[tex] \frac{21}{ \sqrt{14}} = \frac{21 \sqrt{14} }{14} = \frac{3 \sqrt{14} }{2} [/tex]
e)[tex] \frac{5}{ \sqrt{10} } = \frac{5 \sqrt{10} }{10} = \frac{ \sqrt{10} }{2} [/tex]
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b) [tex] \frac{6}{ \sqrt{7} } = \frac{6 \sqrt{7} }{7} [/tex]
c) [tex] \frac{11}{ \sqrt{3} } = \frac{11 \sqrt{3} }{3} [/tex]
d) [tex] \frac{7}{ \sqrt{10} } = \frac{7 \sqrt{10} }{10} [/tex]
e) [tex]- \frac{2}{ \sqrt{3} } = - \frac{2 \sqrt{3} }{3 } [/tex]
2. a) [tex] \frac{4}{ \sqrt{2} } = \frac{4 \sqrt{2} }{2} = 2 \sqrt{2} [/tex]
b) [tex] \frac{6}{ \sqrt{6} } = \frac{6 \sqrt{6} }{6} = \sqrt{6} [/tex]
c) [tex]- \frac{9}{ \sqrt{3} } = \frac{9 \sqrt{3} }{3} = 3\sqrt{3} [/tex]
d)[tex] \frac{21}{ \sqrt{14}} = \frac{21 \sqrt{14} }{14} = \frac{3 \sqrt{14} }{2} [/tex]
e)[tex] \frac{5}{ \sqrt{10} } = \frac{5 \sqrt{10} }{10} = \frac{ \sqrt{10} }{2} [/tex]
Sper ca te-am ajutat!