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fie functia f:(–3;–1;0;1;2) -> B,f(x)=2x+1 determinati multimea B

Răspuns :

f(-3)= -3 *2 +1 = -5
f(-1)=-1*2+1=-1
f(0)= 0*2+1= 1
f(1)=2*1+1=3
f(2)=2*2+1=5
Asadar multimea B={-5,1,3,5}
Sper ca te am ajutat