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Dobrealina84
a fost răspuns

daca x₊y≈7,05 y₊z≈14,1 calculati ₍ x₊ 3y₊2z₎·₍z₋x₎ ?

Răspuns :

(y+z)-(x+y)=y+z-x-y=z-x=14,1-7,05=7,05
x+3y+2z=(7,05-y)+3y+(14,1-y)=y+21,06

₍ x₊ 3y₊2z₎·₍z₋x₎=(y+21,06)x7,05

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