👤
Adynatrendy
a fost răspuns

Fie functia f:R ->R , f(x)=3x+6
Rezolvati in multimea numerelor reale ecuatia 3·f(x)-f(1)=f(2)

Răspuns :

f(1)=9
f(2)=12
3(3x+6)-9=12
9x+18=21
9x=3
x=1/3
Enajarim
f (x) = 3x + 6
f (1) = 3 + 6= 9
f (2) = 6 + 6= 12
3 f(x) - f(1)= f(2)
3 ( 3x+6) - 9 = 12
9x + 18 -9 =12
9x + 9= 12
9x = 3
x =3/9 = 1/3

Alte intrebari