b=2a/3
c=7(a+b)/4=7(a+2a/3)/4=7×5a/12=35a/12
b+c=2a/3+35a/12=(8a+35a)/12=43a/12
b²=(2a/3)²=4a²/9
c²=(35a/12)²=1225a²/144
(ab+ac)/(b²+c² )=
=a(b+c)/(b²+c² )=
=(a×43a)/12/(4a²/9+1225a²/144)=
=(43a²/12)/a²(4/9+1225/144)=
=(43/12)/(4/9+1225/144)=
=(43/12 )/[(64+1225)/144]=
=(43/12 )/(1289/144)=
=43/12 × 144/1289=
=516/1289