Se da
m sol 1 = 20 g
ω1=ω2=10%
De aflat
m Na2SO4-?
m sol 2 (NaOH)-?
R/z:
x 2g y
2NaOH + H2SO4 ⇒Na2SO4 +2H2O
80g/mol 98g/mol 142g/mol
m de H2SO4 =10%*20 g =2g
x=[tex] \frac{80*2}{98} =1.63g[/tex]
m sol 2 = 1.63*10 ( ca solutie de 10 %) =16.3g
y=[tex] \frac{142*2}{98}=2.89g [/tex]
R/s: m Na2SO4=2.89g
m sol 2 (NaOH)=16.3g
