a+b+c = 475
a:b = 3 rest 16
a = 3×b+16
b:c = 2 => b =2×c
a |___|___|___|___|___|___|+16
b |___|___|
c |___|
avem 9 segmente egale+16 = 475
475-16 = 459
459:9 = 51 ( un segment)
a = 6×51+16 = 306+16 = 322
b = 2×51 = 102
c = 51
Verificare:
322+102+51= 475
Numerele sunt:
322; 102; 51.
