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a fost răspuns

IMPARTITI NUMARUL 106 IN PARTI DIRECT PROPORTIONALE CU NUMERELE 0.(3); 2 SI 1,2

Răspuns :

Renatemambouko
0,(3)=3/9=1/3
1,2=12/10=6/5
a/(1/3)=b/2=c/(6/5)
3a=b/2=5c/6
b=2a*3=6a
c=6*3a/5=18a/5
a+6a+18a/5=106
5a+30a+18a=530
53a=530
a=10
b=6*10=60
c=18*10/5=36




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