Răspuns :
283-70=213 bile in primele 3 urne
213:3=71 bile in prima,a doua si a treia urna fiecare iar in a patra 283 bile
213:3=71 bile in prima,a doua si a treia urna fiecare iar in a patra 283 bile
a+b+c+70=238
a=b=c
3a=238-70
a=168:3
a=56-bile
b=56-bile
c=-bile56
P:56+56+56+70=238
a+b+c=56×3=168-bile
a=b=c
3a=238-70
a=168:3
a=56-bile
b=56-bile
c=-bile56
P:56+56+56+70=238
a+b+c=56×3=168-bile