Fie x nr de moli H2O
masa H2O2 = 34
nr de moli × M = 34
nr de moli x 34 = 34 => 1 mol H2O2
1 mol H2O2 contine 2gH2O
6-2 = 4 g, vor fi continute in x moli de H2O
1 mol H2O ...2g H2
x moli H2O....4
x = 2 moli H2O
c%molar H2O = 2/(2+1) ×100 = 66.67%
c%molar H2O2 = 1(2+1) ×100 = 33.33%