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TonnyBarosan
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logx 2 + log2 x > 2 HELPP

Răspuns :

Lennox
Aplici  formula  log(a)b=1/log(b)a
x>0  x≠1
log(x)2+1/log(x)2>2
Notezi log(x)2=y
y+1/y>2
y²-2y+1>0
(y-1)²≥)  Evident ∀y∈R
Revii  la logaritm
(log(x)2-1)²≥0

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