1.2.b N= 15,055x10²³ molec Cl2
1molmolec.......contine 6,023x10²³molec
x....................................15,055x10²³
x,mol= 2,5mol Cl2
1mol............ocupa vol.22,4l
2,5mol..................x=,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,calculeaza
in urma acestor reguli de trei simpla rezulta niste relatii de calcul,pe care le voi folosi mai departe (ti le-am dat si trebuia doar sa faci niste inlocuiri)
10c n=N/N,A=> 24,088X10²³/6,023X10²³=4 mol N2
V= n x Vm=> V=4molx22,4l/mol= ........................calculeaza !!!
d. n=24,088x10la puterea26/ 6,023x10²³=4x10³mol NH3
V=4000mol X22,4l/mol=......................................calculeaza !!!!
