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Asava44
a fost răspuns

Determinati numarul narural "x",daca:

4+8+12+...+396=200x

Răspuns :

Miky93
[tex]4+8+12+...+396=200x \ |:4 \ \ \ (Se \ imparte \ toata \ expresia \ prin \ 4)\\\\ 1+2+3+...+99=50x \\\\ \frac{(1+99)}{2}*99=50x \\\\ \frac{100}{2}*99=50x \\\\ 50*99=50*x \\\\ \boxed{x=99}[/tex]
Deva
4+8+12+...+396=200x     :4
1+2+3+....+99=50x
99x100/2=9900/2=4950
4950=50x
x=4950/50=99

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