Răspuns :
w%(NaCl)=m(NaCl)*100%/m(sol)
m(NaCl)=m(sol)*w%(NaCl)/100%
m(NaCl)=400g *10% /100%=40 g
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adaugin inca 40g de (NaCl)
masa sol creste la fel ca w% shi m(NaCl)
m(sol )=400 +40=440g
w%(NaCl)=m(NaCl)*100%/m (sol)=80g*100%/440g=18.182%
m(NaCl)=m(sol)*w%(NaCl)/100%
m(NaCl)=400g *10% /100%=40 g
--------------------------------------------------------------
adaugin inca 40g de (NaCl)
masa sol creste la fel ca w% shi m(NaCl)
m(sol )=400 +40=440g
w%(NaCl)=m(NaCl)*100%/m (sol)=80g*100%/440g=18.182%
ms1=400g
c1=10% ==>md1=400*10/100=40g
se adauga 40g sare si se obtine o noua solutie cu caracteristicile :
ms2=ms1+40
md2=md1+40=40+40=80
c2=80*100/440=......
c1=10% ==>md1=400*10/100=40g
se adauga 40g sare si se obtine o noua solutie cu caracteristicile :
ms2=ms1+40
md2=md1+40=40+40=80
c2=80*100/440=......