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Betibety2001
a fost răspuns

In 400gsolutie de sare de concentratie 10% se adauga 40g sare
Noua solutie are concentratia procentuala de ?


Răspuns :

w%(NaCl)=m(NaCl)*100%/m(sol)
m(NaCl)=m(sol)*w%(NaCl)/100%
m(NaCl)=400g *10% /100%=40 g
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adaugin inca 40g de (NaCl)
masa sol creste la fel ca w% shi m(NaCl)
 m(sol )=400 +40=440g
w%(NaCl)=m(NaCl)*100%/m (sol)=80g*100%/440g=18.182%

ms1=400g
c1=10%        ==>md1=400*10/100=40g

se adauga 40g sare si se obtine o noua solutie cu caracteristicile :

ms2=ms1+40
md2=md1+40=40+40=80

c2=80*100/440=......