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Niicolletta
a fost răspuns

impartiti numarul 9200 in parti direct proportianale cu numerele 1,75;2,75;3 intreg si 1 pe 6
va rog frumos!!

Răspuns :

Renatemambouko
1,75=175/100=7/4
2,75=275/100=11/4
3 1/6=19/6

a/(7/4)=b/(11/4)=c/(19/6)
4a/7=4b/11=6c/19
b=11*4a/4*7=11a/7
c=19*4a/6*7=38a/21
a+11a/7+38a/21=9200
21a+33a+38a=193200
92a=193200
a=2100
b=11*2100/7=3300
c=38*2100/21=3800

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