[tex]V= \frac{h}{3}( A_{B}+ A_{b}+ \sqrt{ A_{B}* A_{b} } \\ A_{B}=5^2=25 \\ A_{b}=1^2=1 \\ h= \sqrt{3^2-(2 \sqrt{2})^2 } =1 \\ V= \frac{1}{3}(25+1+ \sqrt{25})= \frac{31}{3}cm^3 [/tex]
inaltimea trunchiului am aflat-o separind trapezul dreptunghic cu bazele √2/2 si 5√2/2
