a=numarul mai mare
b=numarul mai mic
c=al treilea numar
a+b+c=2000
a+b=1234
b+c=a ⇒a=b+c
Inlocuim in suma pe a+b=1234:
(a+b)+c=2000
a+b=1234
1234+c=2000
c=2000-1234
c=766
a=b+c
a=b+766
Inlocum pe a si pe b in relatia suma:
a+b+c=2000
b+766+b+766=2000
2b+1532=2000
2b=2000-1532
2b=468
b=468:2
b=234
a=b+766
a=234+766
a=1000
Proba:
a+b+c=1000=234+7666=2000. Corect!
a+b=1000+234=1234 Corect!
b+c=234+766=1000=a Corect!