Aflati numerele a b c stiind ca 2a/3=3b/5=5C/4 si a+b+c=119
scoate b si c in functie de a: b=10a/9; 5c/4=3(10a/9)/5=30a/45 = >
c=(30a/45)*4/5=(2a/3)*(4/5)=8a/15 => inlocuim in ultima relatie b si c:
a+10a/9+8a/15=119, aducem la numitor comun 45 => (45a+50a+24a)=119*45 => 119a=119*45 = > a=45, b=10a/9=50, c=8a/15=24
