aflam lungimea inaltimii
[tex]h= \sqrt{8*32}= \sqrt{4*2*16*2}=16cm \\ [/tex]
ipotenuza
c=8+32=40cm
cateta
[tex]a= \sqrt{32^2+16^2}= \sqrt{1280} =16 \sqrt{5}cm [/tex]
cateta
[tex]b= \sqrt{6^2+16^2}= \sqrt{320}=8 \sqrt{5}cm \\ P=40+16 \sqrt{5}+8 \sqrt{5}=40+24 \sqrt{5}(cm) [/tex]
