se aplica relatia : c=mdx100/ms
c1=20% ms1=200g md1= c1xms1/100= 40g
c2= 60%
a.masa de acid se adauga si la md si la ms
md2= md1+200=240g
ms2=ms1+200=400g
c2= 240x100/400= 60% corect!
deci cad punctele c.si e.
b. scade ms prin evaporarea apaei; md ramane constant
.md2=md1=40g
ms2=ms1-100= 100g
c2=40x100/100=40%---incorect !
d ,se adauga la md1 si la ms1 ,md si ms din a doua solutie
80/100=md/200--> md=160g
md2= md1+160= 2oog
ms2= ms1+200=400g
c2=200x100/400=50% incorect !
