M,Ca= 40g/mol
n(niu)= 20g/40g/mol= 0,5mol
1mol..........................1mol
Ca+ 1/2O2------> CaO
0,5mol......................0,5mol
1mol.....1mol.......1mol
CaO+ H2O---> Ca(OH)2
0,5mol...0,5mol.....0,5mol
m,Ca(OH)2= 0,5molx74g/mol= 37g
m,H2O= 0,5molx18g/mol= 9g
solutia obtinuta contine
md= 37gCa(OH)2 substanta dizolvata inapa
m,apa= m,initial- m,reactionat= 500g-9g=491g
c= mdx100/ms, unde ms= md+m,apa= 37g+491g=528g
c= 37x100/ 528=....................calculeaza !!!!
