Răspuns :
a+r+g=64
r=3*g a=4*g inlocuim in prima relatie
4*g+3*g+g=64 =>8*g=64 =>g=8 =>r=3*8=24 si a=4*g=4*4=32
r=3*g a=4*g inlocuim in prima relatie
4*g+3*g+g=64 =>8*g=64 =>g=8 =>r=3*8=24 si a=4*g=4*4=32
a+r+g=64
r>g de 3 ori
a>g de 4 ori
a|__|__|__|__|
r |__|__|__|__|
g|__|
64:9=7{g}
7×4=28r
7×4=28a
r>g de 3 ori
a>g de 4 ori
a|__|__|__|__|
r |__|__|__|__|
g|__|
64:9=7{g}
7×4=28r
7×4=28a