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Robertdyzy
a fost răspuns

Daca : x+y=7,05 ; y+z=14,1 Calculati: (x+3y+2z)*(z-x)

Răspuns :

x+3y+2z=x+y+2y+2z=(x+y)+2(y+z)=7,05+2*14,1=7,05+28,2=35,25
x+3y+2z=35,25 (1)

z-x=?
y+z=14,1
x+y=7,05
scadem cele doua relatii si rezulta:
z+y-x-y=14,1-7,05
z-x=7,05 (2)

(1)*(2) =(x+3y+2z)*(z-x)=35,25*7,05=248,5125