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a fost răspuns

( x pătrat +3x +3)(x pătrat +3x +4) -2
Descompuneti intrun produs de doi factori primi


Răspuns :

Matematician1234
[tex]-notam~x^2+3x+3=t \\ (x^2+3x+3)(x^2+3x+4)-2=t(t+1)-2=t^2+t-2= \\ =t^2+2t-t-2=t(t+2)-(t+2)=(t+2)(t-1)= \\ =(x^2+3x+3+2)(x^2+3x+3-1)=(x^2+3x+5)(x^2+3x+2)= \\ =(x^2+3x+5)(x^2+x+2x+2)=(x^2+3x+5)(x+1)(x+2)[/tex]