2= [tex] -log_{10} [/tex]|[H+]| => |[H+]| = [tex] 10^{-2} [/tex] = 0.01 M de H+ Cum ionii nu pot exista singuri in solutie, atunci C acidului este = 0.01 M V HCl = 250 ml = 0.25 l C=n/V => n=C x V = 0.01 x 0.25= 0.0025 mol HCl
1 mol H2 ....1 mol Cl2.... 2 mol HCl a mol H2 ....b mol Cl2....0.0025 mol HCl a=0.0025/2 = 0.00125 mol H2 => V H2 (cn) = 0.00125 x 22.4 = 0.028 L H2 b= 0.0025/2 = 0.00125 mol Cl2=> V Cl2 (cn) = 0.00125 x22.4 = 0.028 L Cl2