2 CH4 => C2H2 + 3 H2
r=80%
8 mol Metan ... 4 mol acetilena (ct)
r=[tex] \frac{cp}{ct} [/tex]× 100
cp = r x ct /100
cp= 80 x4/100 =3.2 mol
r=randament
cp =cantitate practica
ct= cantitate teoretica
C2H2 + HCN => C2H3-CN
1 mol C2H2.... 1 mol HCN
3.2 mol C2H2 ...a mol HCN
a= 3.2 mol HCN