z=a+bi
z²=(a+bi)²=a²+b²+2abi
lzl=√(a²+b²)
a²+b²+√(a²+b²)+2abi=0
Sistem
{a²+b²+√(a²+b²)=0
{a²+b²+√(a²+b²)=0 (1
{2ab=0 => a=0 sau b=0
caz 1. a=0
0²+b²+√b²=0 b²+lbl=0 =>
b²-b=0 b<0 b(b-1)=0 b1=0 b2=1>0
b²+b=0 b≥0
b1=-1∉[0,∞) b=0∈[0,∞)
z=0
Analog procedezi pt caz 2) b=0
