👤
Tranca45
a fost răspuns

rezolva operatiile urmatoare:
a) [(102x14+42x20-1968):100+(13452:38+92x10+2696):1000]:7=
b) [121-80:(1596:57+4992:96)-20(1750:25-3000:60)]-199=
c) 6000-[(48x16+36x18+69):45+(1105:85+97x36)]=

Răspuns :

Dennysa21
a) [(102×14+42×20-1969):100+(13452:38+92×10+2696):1000]:7=
=[(1428+840-1969):100+(354+920+2696):1000]:7
=(299:100+3970:1000):7
=(2,99+3,97):7=6,96:7=0,99
c)6000-[(48×16+36×18+69):45+(1105:85+97×36)]=
=6000-[(768+648+69):45+(13+3492)]
=6000-(1485:45+3505)
=6000-(33+3505)=6000-3538=2462

Alte intrebari