👤
Didi316
a fost răspuns

suma a trei numere consecutive este 57.

Răspuns :

Cataclyzmic
a
b= a+1
c= b+1 = a+2
a+b+c = 57
a+a+1+a+2=57
3a +3=57
3a= 57-3
3a=54
a=54/3
a=18
Icecon2005
a,b,c consecutive
a, b=a+1, c=a+2
a+(a+1)+(a+2)=57
3a+3=57⇒3a=57-3⇒3a=54⇒a=54:3⇒a=18
b=a+1=18+1=19
c=a+2=18+2=20
verificare
a+b+c=18+19+20=57⇒57=57
deci numerele sunt: 18,19,20