👤
a fost răspuns

(37^2016:1369^1008) : (2^2016-2^2015-...-2^2-2-1)=??? PLZZ AJUTATIMA!!!
!

Răspuns :

[tex]Notam:\\ S=1+2+2^2+...+2^{2015}|\cdot 2\\ 2S=2+2^2+2^3+...+2^{2016}\\ -------------\\ 2S-S=2^{2016}-1\\ S=2^{2016}-1\\ Revenind:\\ {[37^{2016}:(37^2)^{1008}]:(2^{2016}-2^{2016}+1)}=\\ (37^{2016}:37^{2016}):1=\\ 1:1=1[/tex]